(1) Check If A Number Is Positive, Negative or 0.
num = float(input('Enter A Number '))
if num > 0:
print('Positive Number')
elif num < 0:
print('Negative Number')
else:
print('Zero')
(2) Check If A Number Is Odd or Even.
num = float(input('Enter A Number'))
if num % 2 == 0:
print('Even Number')
else:
print('Odd Number')(3) Check A Year Is Leap Year Or Not.
- We have discussed above, we know that because the Earth rotates about 365.242375 times a year but a normal year is 365 days, something has to be done to “catch up” the extra 0.242375 days a year.
So every fourth year we add an extra day (the 29th of February), which makes 365.25 days a year. This is fairly close but is wrong by about 1 day every 100 years.
So every 100 years we don’t have a leap year, and that gets us 365.24 days per year (1 day less in 100 years = -0.01 days per year). Closer, but still not accurate enough!
So another rule says that every 400 years is a leap year again, this gets us 365.2425 days per year (that is 1 day regained every 400 years equals 0.0025 days per year), which is close to 365.242375 not to matter much.
# Python program to check if year is a leap year or not
year = 2000
# To get year (integer input) from the user
# year = int(input("Enter a year: "))
# divided by 100 means century year (ending with 00)
# century year divided by 400 is leap year
if (year % 400 == 0) and (year % 100 == 0):
print("{0} is a leap year".format(year))
# not divided by 100 means not a century year
# year divided by 4 is a leap year
elif (year % 4 ==0) and (year % 100 != 0):
print("{0} is a leap year".format(year))
# if not divided by both 400 (century year) and 4 (not century year)
# year is not leap year
else:
print("{0} is not a leap year".format(year))(4) Find The Largest Among Three Numbers.
num1 = 10
num2 = 14
num3 = 12
largest = 0
if (num1>=num2) and (num1>=num3):
largest = num1
elif (num2>=num1) and (num2>=num3):
largest = num2
else:
largest = num3
print(largest)14(5) Check A Number Is Prime Number Or Not.
A positive integer greater than 1 which has no other factors except 1 and the number itself is called a prime number. 2, 3, 5, 7 etc. are prime numbers as they do not have any other factors.
But 6 is not prime (it is composite) since,
2 x 3 = 6.
# Program to check if a number is prime or not
num = 29
# To take input from the user
#num = int(input("Enter a number: "))
# define a flag variable
flag = False
if num == 1:
print(num, "is not a prime number")
elif num > 1:
# check for factors
for i in range(2, num):
if (num % i) == 0:
# if factor is found, set flag to True
flag = True
# break out of loop
break
# check if flag is True
if flag:
print(num, "is not a prime number")
else:
print(num, "is a prime number")29 is a prime number(6) Print All Prime Numbers In An Interval
- We can use ‘for’ with ‘else’ block to do this operation.
- The
elsekeyword in aforloop specifies a block of code to be executed when the loop is finished. - The
elseblock will NOT be executed if the loop is stopped by abreakstatement.
# Python program to display all the prime numbers within an interval
lower = 900
upper = 1000
print("Prime numbers between", lower, "and", upper, "are:")
for num in range(lower, upper + 1):
# all prime numbers are greater than 1
if num > 1:
for i in range(2, num):
if (num % i) == 0:
break
else:
print(num)Prime numbers between 900 and 1000 are:
907
911
919
929
937
941
947
953
967
971
977
983
991
997(7) Find The Factorial of A Number
- The factorial of a number is the product of all the integers from 1 to that number.
- For example, the factorial of 6 is
1*2*3*4*5*6 = 720. - Factorial is not defined for negative numbers, and the factorial of zero is one,
0! = 1.
# Python program to find the factorial of a number provided by the user.
# change the value for a different result
num = 7
# To take input from the user
#num = int(input("Enter a number: "))
factorial = 1
# check if the number is negative, positive or zero
if num < 0:
print("Sorry, factorial does not exist for negative numbers")
elif num == 0:
print("The factorial of 0 is 1")
else:
for i in range(1,num + 1):
factorial = factorial*i
print("The factorial of",num,"is",factorial)
(8) Display The Multiplication Table
- In the program below, we have used the for loop to display the multiplication table of 12.
# Multiplication table (from 1 to 10) in Python
num = 12
# To take input from the user
# num = int(input("Display multiplication table of? "))
# Iterate 10 times from i = 1 to 10
for i in range(1, 11):
print(num, 'x', i, '=', num*i)
12 x 1 = 12
12 x 2 = 24
12 x 3 = 36
12 x 4 = 48
12 x 5 = 60
12 x 6 = 72
12 x 7 = 84
12 x 8 = 96
12 x 9 = 108
12 x 10 = 120(9) Python Program To Print Fibonacci Series.
- A Fibonacci sequence is the integer sequence of 0, 1, 1, 2, 3, 5, 8….
- The first two terms are 0 and 1.
- All other terms are obtained by adding the preceding two terms. This means to say the nth term is the sum of (n-1)th and (n-2)th term.
# Program to display the Fibonacci sequence up to n-th term
nterms = int(input("How many terms? "))
# first two terms
n1, n2 = 0, 1
count = 0
# check if the number of terms is valid
if nterms <= 0:
print("Please enter a positive integer")
# if there is only one term, return n1
elif nterms == 1:
print("Fibonacci sequence upto",nterms,":")
print(n1)
# generate fibonacci sequence
else:
print("Fibonacci sequence:")
while count < nterms:
print(n1)
nth = n1 + n2
# update values
n1 = n2
n2 = nth
count += 1Enter A Positive Number10
0
1
1
2
3
5
8
13
21
34